From the given diagram, using the property of similar Triangle we can write
[tex] \\
\
\frac{60}{60+27}=\frac{80}{80+2x}\\
\\
\
\frac{60}{87}=\frac{80}{80+2x}\\
\\
\Rightarrow 60(80+2x)=80*87\\
\\
\
\Rightarrow 80+2x=116\\
\\
\Rightarrow x=18\\
[/tex]
