1/2 [3logx + logy]
Step 1:
we use the property of n logx =log xⁿ for 3 logx
so 1/2[3logx +logy]= 1/2 [log x³ + log y]
Step 2:
We use another property here log a + log b = log (ab)
1/2[log x³y]
Step 3:
we again use the property of n logx =log xⁿ, bringing 1/2 in power
[log x³y]^1/2
√log(x³y)
