afrahomroowwl1s afrahomroowwl1s

03-03-2019
Physics

contestada

The illuminance on a surface is 3.5 lux, and the surface is 2 meters from the light source. What’s the intensity of the source?

Respuesta :

wiseowl2018 wiseowl2018

03-03-2019

Answer:

The intensity is 49 Candelabra

Explanation:

The formula for calculation the luminous intensity is;

Luminous intensity = illuminance × square radius

Lv = Ev × r²

= 3.5 × 2²

= 3.5 × 14

= 49 Candelabra

Answer Link

Otras preguntas

[tex]18 {x}^{2} - x - 39 [/tex]How to solve this

Which of the following expressions are equivalent to 6.53 - (-4.11) + 7.926.53?(Choice A)A6.53-(-4.11+7.92)6.53−(−4.11+7.92)6, point, 53, minus, left parenthesi

718.521 rounded to the nearest one

all numbers are divisible by

Determine the resistance of 150m of single copper cable whose CSA is 10mm². Take the resistivity of copper to be 17.2 x 10° ohm/metre'.

Krista bought the same number of pencils and erasers with $252. Each eraser costs $18. How many erasers did she purchase?

What’s the answer?? Please

Marcos prefiere ____ con su padre. vivir visita habla vive

Plssssssssssssssssssss Answer this is Major?This activity will help you meet these educational goals:You will create a quadratic function to model the area of a

p= -5x2 + 70x - 165