corinam9851 corinam9851

02-04-2019
Chemistry

contestada

How many ml of 0.0500 m cacn2 are needed to make 25.0 ml of 0.0150 m solution? The molar mass of cacn2 is 80.11 g/mol.

Respuesta :

11-04-2019

Answer:

= 7.50 mL

Explanation:

m1v1=m2v2

In this case;

m1=0.05

m2=0.015 and

v2=25.00mL

Therefore;

(.0500M)(v1)=(25.00mL)(.0150M)

V1 = ((25.00mL)(0.0150M))/0.0500 M

= 7.50 mL

Answer Link

Otras preguntas

Find the interval(s) over which the function is increasing

What was a consequence of Russia with drawing from world war 1

If the measure of angle ABF=6x+26 and the measure of angle EBF=2x9 and measure of angle ABE= 11x-31 find the measure of angle ABF

How are hydrogen bonds different from covalent bonds? A) The atoms in hydrogen bonds have valence electrons B) The compounds that result from hydrogen bonds co

Solve the following equation then place the correct number in the box provided 3(2x+5)> 2(x+6)

which are characteristics of a desert ecosystem? choose all that apply 1.dry and hot 2. dry and cold 3. many plants grow here 4. receives less than ten inches

Select the correct text in the passage. Which sentence in this excerpt from Franklin D. Roosevelt’s “Four Freedoms” speech suggests that the US government would

What does the atomic number of an element tell us?

Does 14.2857143 round to a whole number

how do you say american in spanish