Answer:
12,558 J
Explanation:
The amount of heat absorbed by the water is given by:
[tex]Q=mC_S \Delta T[/tex]
where
m = 50 g is the mass of the water
[tex]C_s = 4.186 J/gC[/tex] is the water specific heat
[tex]\Delta T=90C-30C=60^{\circ}C[/tex] is the temperature increase of the water
Substituting into the formula, we find
[tex]Q=(50.0 g)(4.186 J/gC)(60^{\circ}C)=12,558 J[/tex]
