Seudónimo Seudónimo

02-05-2016
History

contestada

Solve ax2 + bx +c = 0 when a=5, b = -23 and c = 12 to find the zeros (x intercepts)

Respuesta :

konrad509 konrad509

02-05-2016

[tex]5x^2-23x+12=0\\ 5x^2-20x-3x+12=0\\ 5x(x-4)-3(x-4)=0\\ (5x-3)(x-4)=0\\ x=\dfrac{3}{5} \vee x=4 [/tex]

Answer Link

Otras preguntas

It is given that the straight line y = (q + 2)x + 10 is parallel to the straight line 4x + 2y = 5. Find the value of q.

(Marking Brainliest) What is the vertex form of the equation?y = x^2 - 4x + 7

Giving 50 Points for this!!

all rules to find work in changing force in physics

Write a paragraph in which you consider at least three differences between acquiring English and learning Standard English.

Which ordered pair is a solution to the equation? -3x + 5y = 2x + 3y A) Only (2, 4) B) Only (3, 3) C) Both (2, 4) and (3, 3) D) Niether

20. What is political Nullification? 1 A way of balancing a budget by borrowing2 If a state finds a federal law unconstitutional it has the right to "nullify" t

Why did George Washington warn against political parties?

A 27 y/o female came in with severe abdominal pain, nausea, vomiting, tenderness on the RLQ, and positive McBurney's point. Her vitals are as follows: BP: 120/8

Evelyn bought snacks for her team's practice. She bought a bag of chips for $2.99 and a 20-pack of juice bottles. The total cost before tax was $36.39. Write an