Answer:
Step-by-step explanation:
Given that a line passes through a point
P = (5, 0, 3)
Direction vector = [tex]v = 3, 0, 5[/tex]
Let (x,y,z) =r(t) be any general point on the line
We have
[tex]x-5, y-0, z-3[/tex] will be proportional to v
Or [tex]\frac{x-5}{3} =\frac{y}{0} =\frac{z-3}{5}[/tex]
Let this equals t
Then parametric form
= [tex]r(t) = (5+3t)i +0.j+(3+5t)k[/tex]
