Answer:
160 g.
Explanation:
The balanced equation is
4Fe + 3O2 ---> 2Fe2O3.
4 * 56 g of Fe reacts with 6 * 16 g of O2 to give 2 * 160 g Fe2O3.
224 g Fe reacts with 96g of O2 to give 320 g Fe2O3.
So 48 g O2 + 224 g Fe produces 320 * 1/2 = 160 g Fe2O3.
