Respuesta :

mariamikayla
[tex]9^{x-5} =27 \\\\ 3^{2(x-5)}= 3^3 \\\\ 2(x-5)=3 \\\\ 2x-10=3 \\\\ 2x=3+10 \\\\ 2x=13 \\\\ \boxed{x=\frac{13}{2}}[/tex]
konrad509
[tex]9^{x-5}=27\\ 3^{2(x-5)}=3^3\\ 2(x-5)=3\\ 2x-10=3\\ 2x=13\\ x=\frac{13}{2}[/tex]