cblack4real
cblack4real cblack4real
  • 01-11-2020
  • Mathematics
contestada

If the equation y² - (K-
2y + 2k +1 = 0
with equal roots find the value of k​

Respuesta :

Lightning25346
Lightning25346 Lightning25346
  • 01-11-2020

Answer:

y² - (K-  2)y + 2k +1 = 0

equal roots means D=0

D= b^2 - 4ac

a=1, b= (k-2), c= 2k+1

so,

(k-2)^2 - 4(1)(2k+1) = 0

=> k^2 +4 - 8k -4 = 0

=> k^2 -8k = 0

=> k^2 = 8k

=> k= 8k/k

=> k = 8

Therefore the answer is k= 8

Hope it helps........

Answer Link

Otras preguntas

 Cabbage grows better in basic soil. In which TWO of the soil samples should cabbage grow well? A,B,C,D,E?
What major problems could you encounter in complex intersections?
What is the connection between ambition, power, and corruption? explain (2 paragraphs)
how did the tigris and euphrates enable mesopotamia to flourish
Write a function that takes as input a single parameter storing a list of integers and returns the minimum, maximum, and average values of the list as a tuple.
What is an example of an event or occasion where you would set the table?
rewrite the sentence adding a nonrestrictive element using commas : Carters van needs to be washed. Can someone help please
I just need help on this one question If you help this is worth 30 points
how do i solve 4x^2 = 20x - 25
risou no musume nara sekai saikyou demo kawaigatte kuremasuka