Answer:
[tex]x=-0.75,3[/tex]
Step-by-step explanation:
We can use the quadratic formula to solve for [tex]x[/tex]:
Given equation: [tex]4x^2-9x-9=0[/tex]
[tex]x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}[/tex] (using quadratic formula, [tex]ax^2+bx+c = 0[/tex])
[tex]x=\frac{9\pm\sqrt{(-9)^2-4(4)(-9)} }{2(4)}[/tex] (substitute numbers in)
[tex]x=\frac{9\pm\sqrt{225} }{8}[/tex]
[tex]x=-0.75,3[/tex]
Hope this helps :)
