Question:
Solve the equation 2x2−5x+3=0 by the method of completing square.
Answer:
We have,
2x2−5x+3=0
⇒x2−25x+23=0 (Dividing throughough by 2)
⇒x2−25x=−23 (Shifting the constant term on RHS)
⇒x2−2(45)x+(45)2=(45)2−23 (Adding (21Coeff.ofx)2 onboth sides)
⇒(x−45)2=1625−23⇒(x−45)2=16
