Answer:
g=e+f
Step-by-step explanation:
e= (-1,5)=-1i+5j
f=(3,-4)=3i-4j
g=(2,1)=2i+j
Let there exist real constant a,b:
ae+bf=g
For i: -a+3b=2
For j: 5a-4b=1
[tex]\left[\begin{array}{ccc}-1&3&2\\5&-4&1\end{array}\right][/tex]
Solves and gives:
a=1
b=1
g=e+f
