Answer:
e^{sin²x}+c
Step-by-step explanation:
[tex]\int e^{sin^2x} sin 2x dx=?[/tex]
is this statement?
if so
then
[tex]put~sin^2x=t\\differentiate\\2 sin ~x~cos~x~dx=dt\\sin~2x ~dx=dt\\\int e^t~dt=e^t+c\\=e^{sin^2x}+c[/tex]
