Answer:
c = 8
Step-by-step explanation:
[tex] \dfrac{(p^2)^3}{p^c} = p^5 \times p^{-7} [/tex]
[tex] \dfrac{p^6}{p^c} = p^{-2} [/tex]
[tex] p^{6-c} = p^{-2} [/tex]
[tex] 6 - c = -2 [/tex]
[tex] -c = -8 [/tex]
[tex] c = 8 [/tex]
