Answer:
x>3
Step-by-step explanation:
Work:
2x^2-x>15
Subtract 15 on both sides:
2x&2-x-15>0
Factor the left side of equation to cancel out the ^2.
(2x+5)(x−3)>0
2x+5=0 or x−3>0
Then to make it easier we will do the x-3>0 one, add 3 to both sides = x>3
