Answer:
Solution,
hypotenuse (h)=x
perpendicular(p)=9
base(b)=53°
Using pythagoras theorem,
[tex] {h}^{2} = {p}^{2} + {b}^{2} [/tex]
[tex] {x}^{2} = {9}^{2} + {53}^{2} [/tex]
[tex] {x}^{2} = 81 + 2809[/tex]
[tex] {x}^{2} = 2890[/tex]
[tex]x = \sqrt{2890} [/tex]
[tex]x = 53.75[/tex]
hope it helps you
