Answer: A=2, B=5, C=4
Step-by-step explanation:
[tex]\frac{6x^{2}+13x-5}{x^{2}-16} \cdot \frac{x+4}{3x-1}\\\frac{(3x-1)(2x+5)}{(x-4)(x+4)} \cdot \frac{x+4}{3x-1}\\\frac{2x+5}{x-4}[/tex]
So A=2, B=5, and C=4.
