Solution
For this case we have the following terminal point:
a) -7pi/6
The reference angle is pi/6
The quadrant is II
The terminal point is:
[tex](-\frac{\sqrt[]{3}}{2},\frac{1}{2})[/tex]b) -41 pi/4
The reference angle is pi/4
The quadrant is IV
The terminal point is:
[tex](\frac{\sqrt[]{2}}{2},-\frac{\sqrt[]{2}}{2})[/tex]