[tex]\begin{gathered} \frac{3in}{1\text{ ft}}\text{ = }3 \\ \text{Solving the option B : }\frac{2}{\frac{2}{3}} \\ \text{ 2 }\frac{\cdot}{\cdot}\text{ }\frac{2}{3} \\ \text{ }\frac{2}{1}\text{ }\frac{\cdot}{\cdot}\text{ }\frac{2}{3} \\ \text{ }\frac{2}{1}\times\frac{3}{2}\text{ = }\frac{6}{2}\text{ = 3} \end{gathered}[/tex]
