Given
[tex]\begin{gathered} IH=5 \\ IJ=9 \end{gathered}[/tex]
We can find the measure of I below.
Explanation
[tex]\begin{gathered} CosI=\frac{Adjacent\text{ }side}{Hypotenuse\text{ side}}=\frac{IH}{IJ}=\frac{5}{9} \\ I=Cos^{-1}\frac{5}{9} \\ I=Cos^{-1}0.98176 \\ I=56.3^{\circ\:} \end{gathered}[/tex]
Answer:
[tex]I=56.3^0[/tex]
