Given
[tex]x^2+x-2\ge0[/tex]
To find the solution.
Now,
It is given that,
[tex]x^2+x-2\ge0[/tex]
Using factorization method,
[tex]\begin{gathered} x^2+x-2=0 \\ x^2-x+2x-2=0 \\ x(x-1)+2(x-1)=0 \\ (x+2)(x-1)=0 \end{gathered}[/tex]
That implies,
[tex]\begin{gathered} x+2\ge0,x-1\ge0 \\ x\ge-2,x\ge1 \end{gathered}[/tex]
Hence, the solution set is,
[tex]undefined[/tex]
