Respuesta :

mreijepatmat
u(x)=-2x²+3
v(x)=1/x →→ range of (uоv)(x, BUT  range (uov)(x  = u(v(x)), then :

u(v(x)) = -2(1/x²) + 3 →→u(v(x)) = -2/x² + 3

The range of -2/x² + 3 = {x∈R/x≠0}