Respuesta :

the answer is 2+i I believe
[tex]\frac{8}{2+2i}=\\ \frac{8}{2+2i}*\frac{2-2i}{2-2i}=\\ \frac{16-16i}{4-4i^2}=\\ \frac{16-16i}{4+4}=\\ \frac{16-16i}{8}=\\ 2-2i[/tex]

so it is the first option

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