Respuesta :

gmany
[tex]y=5x;\ (x;\ y)\\\\for\ x=0\to y=5\cdot0=0\to(0;\ 0)\\\\for\ x=2\to y=5\cdot2=10\to(2;\ 10)\\\\for\ x=-2\to y=5\cdot(-2)=-10\to(-2;-10)\\\\for\ x=\dfrac{1}{5}\to y=5\cdot\dfrac{1}{5}=1\to\left(\dfrac{1}{5};\ 1\right)\\\\\for\ x=-10\to y=5\cdot(-10)=-50\to(-10;-50)[/tex]

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